Suppose $\{x_n\}$ is a decreasing sequence that $\displaystyle\lim_{n \rightarrow\infty}x_n=0$. Prove that $\sum(-1)^nx_n$ is convergent
Problem
Source: Iran 2005
Tags: limit, algebra proposed, algebra
27.08.2005 17:04
It is known in France as the 'theorème spécial pour les séries altérnées', and it is part of any course on series... Pierre.
06.09.2005 03:12
In english, it's the alternating series test. The idea is that we can put $\sum^{n}_{i=0} (-1)^i=A_n$, and then write $\left|\sum^q_{i=p} (-1)^ix_i\right|=\left|\sum^{q-1}_{i=p} A_i(x_i-x_{i+1})-A_qx_q-A_{p-1}x_p\right|$ $A_i\leq 1$ for each $i$, so we have $\left|\sum^{q-1}_{i=p} A_i(x_i-x-{i+1})-A_qx_q-A_{p-1}x_p\right|\leq \left|\sum^{q-1}_{i=p} (x_i-x_{i+1})-x_q-x_p\right|=2x_p$ But as $p\to\infty$, $x_p\to 0$, so we have convergence from the Cauchy criterion (that is, Cauchy sequences converge in $\mathbb{R}$).
20.09.2006 06:56
$A_{2n}$ decreasing and $A_{2n+1}$ increasing $A_{2n+1}-A_{2n}=-s_{2n+1}$ $\Rightarrow $ QED
06.06.2016 14:00
Why do I think the only sequence is Xn=0 since Xn is decreasing?