How many ways are there to divide a $2\times n$ rectangle into rectangles having integral sides, where $n$ is a positive integer?
Problem
Source: Turkey, TST D1, P2
Tags: geometry, rectangle, calculus, integration, function, combinatorics proposed, combinatorics
11.05.2006 18:19
Valentin Vornicu wrote: How many ways are there to divide a $2\times n$ rectangle into rectangles having integral sides, where $n$ is a positive integer? This seems interesting, however, are two divisions considered different if they differ only in the placement of the different subrectangles? Daniel
06.06.2006 12:04
to dhernandez: I think it should be considered different. and based on this ,I got the number is $\frac{4+\sqrt{2}}{14}*(3+\sqrt{2})^n+\frac{4-\sqrt{2}}{14}*(3-\sqrt{2})^n$
08.06.2006 01:18
Hawk Tiger could you please post your solution
18.07.2006 22:32
You can use the fact that every rectangle placed across(parallel to the side of length $2$) will create two $2Xk$ rectangles, and then you could find a recursion relation.
23.03.2007 22:26
Well i solved this problem, but i took a lot of time calculating the final formula. I found the recurrence $r_{n}= 6r_{n-1}-7 r_{n-2}$ this was easy with $r_{1}= 2$ and $r_{2}=8$. I know how to solve this recurrence relations in two ways, gerenating functions or solving the caracteristic equation. Is there a faster way of finding the general term? I don't think there exists a way to count this without using recurrences, is there? I hope someone can help.
31.12.2007 15:29
jasamper88 wrote: Well i solved this problem, but i took a lot of time calculating the final formula. I found the recurrence $ r_{n} = 6r_{n - 1} - 7 r_{n - 2}$ this was easy with $ r_{1} = 2$ and $ r_{2} = 8$. I know how to solve this recurrence relations in two ways, gerenating functions or solving the caracteristic equation. Is there a faster way of finding the general term? I don't think there exists a way to count this without using recurrences, is there? I hope someone can help. Please explain how did you get that recursion.