THis must be a joke! Problem 6? If my computations aren't wrong, then denoting $ s=x+y$ and $ p=xy$ we find that $ 2p(s-4)=s^3-8s^2+8$. Thus, it follows that $ s-4| s^3-4s^2-4(s^2-16)+56$ and so $ s-4| 56$. Also, s must be even. Then one can only check for the cases, find p and find x and y.Bleah!