Problem

Source: 2011 Philippine Math Olympiad National Stage Problem 2

Tags: geometry, geometric transformation, reflection



In triangle $ABC$, let $X$ and $Y$ be the midpoints of $AB$ and $AC$, respectively. On segment $BC$, there is a point $D$, different from its midpoint, such that $\angle{XDY}=\angle{BAC}$. Prove that $AD\perp BC$.