Problem

Source: Serbian National Olympiad 2013, Problem 3

Tags: geometry, circumcircle, trigonometry, ratio, symmetry, geometric transformation, reflection



Let $M$, $N$ and $P$ be midpoints of sides $BC, AC$ and $AB$, respectively, and let $O$ be circumcenter of acute-angled triangle $ABC$. Circumcircles of triangles $BOC$ and $MNP$ intersect at two different points $X$ and $Y$ inside of triangle $ABC$. Prove that \[\angle BAX=\angle CAY.\]