Problem

Source: Tuymaada 2012, Problem 8, Day 2, Seniors

Tags: abstract algebra, graph theory, combinatorics proposed, combinatorics



Integers not divisible by $2012$ are arranged on the arcs of an oriented graph. We call the weight of a vertex the difference between the sum of the numbers on the arcs coming into it and the sum of the numbers on the arcs going away from it. It is known that the weight of each vertex is divisible by $2012$. Prove that non-zero integers with absolute values not exceeding $2012$ can be arranged on the arcs of this graph, so that the weight of each vertex is zero. Proposed by W. Tutte