Problem

Source: Turkey IMO TST 1995 #4

Tags: geometry, perpendicular bisector, angle bisector, geometry unsolved



In a convex quadrilateral $ABCD$ it is given that $\angle{CAB} = 40^{\circ}, \angle{CAD} = 30^{\circ}, \angle{DBA} = 75^{\circ}$, and $\angle{DBC}=25^{\circ}$. Find $\angle{BDC}$.