A country has two capitals and several towns. Some of them are connected by roads. Some of the roads are toll roads where a fee is charged for driving along them. It is known that any route from the south capital to the north capital contains at least ten toll roads. Prove that all toll roads can be distributed among ten companies so that anybody driving from the south capital to the north capital must pay each of these companies. (5 points)
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Tags: combinatorics unsolved, combinatorics
03.09.2010 13:50
Let $R$ be the set of all routes from $A$ to $B$. For each route we take the very first toll road and give it to company $C_1$, so clearly every car that goes from $A$ to $B$ has to pay a toll to $C_1$. Suppose $C_1$ makes all its toll roads free and now there exists a route, $r$, from $A$ to $B$ that has $8$ or less toll roads. This means that the route $r$ contains at least $2$ toll roads that belong to $C_1$, however the very last toll road on the route that belongs to $C_1$ is also the first toll road of some other route, $r'$ (because of how we selected $C_1$). Now route $r'$ goes through at most $9$ toll roads which contradicts our original assumption. Hence each route from $A$ to $B$ still goes through at least $9$ toll roads that do not belong to $C_1$. Now we can continue this process giving the first toll road from each route that doesn't already blong to $C_1$ to $C_2$ etc. Such that $10$ companies all own toll roads on every route from $A$ to $B$ $\square$
31.12.2019 20:21
Let the southern capital be $A$ and the northern one be $B.$ For each town/capital in the country, label it with the number $x \ge 0$ which is the minimum number of toll roads one must use to travel from $A$ to this town. A few observations follow. Observation 1. Any two cities with are connected with a road and have different labels must be connected with a toll road. Proof. If one has a greater label than the other and the road connecting them isn't a toll road, then we can travel first to the town with smaller label with the minimum possible number of toll roads, then travel directly to the other town. This is a contradiction. $\blacksquare$ Observation 2. Any two cities connected with a toll road have labels differing by at most $1.$ Proof. Proof similar as the above proof (suppose that one has label greater than the other one by at least $2$). $\blacksquare$ With the above observations, we are ready to finish. For $0 \le i \le 9$, if a toll road connects two cities with labels $i$ and $i+1$, then we grant this road to company $i$. All other toll roads (which must connect two cities with the same label) are distributed arbitrarily amongst the companies. We claim that this works. Indeed, consider some path from $A$ to $B.$ Since the label of $B$ is at least $10$, for each $0 \le i \le 9$, there must be a town on the path which has label $i+1$ (by Observations $1, 2$, the labels of adjacent vertices differ by at most one), and so the road leading into this town must be a toll road belonging to company $i$ (Observations $1, 2$). This concludes the proof. $\square$