Problem

Source: ARO 2005 - problem 11.7

Tags: geometry, incenter, parallelogram, trigonometry, complex numbers, Russia



A quadrilateral $ABCD$ without parallel sides is circumscribed around a circle with centre $O$. Prove that $O$ is a point of intersection of middle lines of quadrilateral $ABCD$ (i.e. barycentre of points $A,\,B,\,C,\,D$) iff $OA\cdot OC=OB\cdot OD$.