There is an Equilateral trapezoid ABCD. ¯AB=60,¯BC=¯DA=36,¯CD=108. M is the middle point of ¯AB, and point P on ¯AM follows that ¯AP =10. The foot of perpendicular dropped from P to ¯BD is E. ¯AC∩¯BD is F. Point X is on ¯AF which follows ¯MX=¯ME Find ¯AXׯAF