The triangles you can make with 8 vertex is 8C3=56 but if the the 3 vertex are in the same line it will not make a triangle. In this case we get 5 sets of 3 vertex which are in the same line like the image bellow. So the answer is 56-5=51. answer:51

The number of ways to choose 3 points from 8 is 8C3=56. However, to form a triangle, the 3 points must not lie on a straight line. There are 5 cases where the 3 points are collinear, so the total number of ways to choose 3 points that form a triangle is 56 - 5 = 51. The answer is 51.

There are $8$ points so the number of ways to make a triangle by choosing 3 vertices is $$\binom{8}{3}=56.$$However, we are overcounting where three points are collinear. We can see by carefully examining the diagram that there are 5 places where three points are collinear (4 straight lines going up and down and 1 diagonal line from one corner to the other). So the answer is $$\binom{8}{3}-5=56-5=\boxed{51}.$$

Ways to choose vertices - collinar = 8C3 - 5 = 56-5 = 51

There are $$ \binom{8}{3} = 56 $$ways to choose 3 different points from 8. But we should exclude methods where three points exist one line. There are 5 such methods, so the answer is : 56 - 5 = 51.