Let \( X \) be an arbitrary point on the side \( BC \) of triangle \( ABC \). The point \( M \) on the ray \( AB^\to \) beyond \( B \), the point \( N \) on the ray \( AC^\to \) beyond \( C \), and the point \( K \) inside \( ABC \) are such that \( \angle BMX = \angle CNX = \angle KBC = \angle KCB \). The line through \( A \), parallel to \( BC \), intersects the line \( KX \) at point \( P \). Prove that the points \( A \), \( P \), \( M \), \( N \) lie on a circle.
Problem
Source: XIII International Festival of Young Mathematicians Sozopol 2024, Theme for 10-12 grade
Tags: geometry