A parallelogram $ABCD$ is given. The incircle of triangle $ABC$ with center $I$ touches $AB,BC,CA$ at $R,P,Q$. Ray $DI$ intersects segment $AB$ at $S$. It turned out that $\angle DPR=90$ Prove that the circle with diameter $AS$ is tangent to the circumcircle of triangle $DPQ$ M. Zorka