Problem

Source: Belarus TST 2024

Tags: algebra, system of equations, number theory



Six integers $a,b,c,d,e,f$ satisfy: $\begin{cases} ace+3ebd-3bcf+3adf=5 \\ bce+acf-ade+3bdf=2 \end{cases}$ Find all possible values of $abcde$ D. Bazyleu