Problem

Source: Ukrainian Mathematical Olympiad 2024. Day 1, Problem 8.3

Tags: geometry



Points $X$ and $Y$ are chosen inside an acute triangle $ABC$ so that: $$\angle AXB = \angle CYB = 180^\circ - \angle ABC, \text{ } \angle ABX = \angle CBY$$ Show that the points $X$ and $Y$ are equidistant from the center of the circumscribed circle of $\triangle ABC$. Proposed by Anton Trygub