Problem

Source: Polish MO Second round 2024 P4

Tags: combinatorics



Let $n$ be a positive integer. A regular hexagon $ABCDEF$ with side length $n$ is partitioned into $6n^2$ equilateral triangles with side length $1$. The hexagon is covered by $3n^2$ rhombuses with internal angles $60^{\circ}$ and $120^{\circ}$ such that each rhombus covers exactly two triangles and every triangle is covered by exactly one rhombus. Show that the diagonal $AD$ divides in half exactly $n$ rhombuses.