Let $\omega_1$ and $\omega_2$ be two circles with no common points, such that any of them is not inside the other one. Let $M, N$ lie on $\omega_1, \omega_2$, such that the tangents at $M$ to $\omega_1$ and $N$ to $\omega_2$ meet at $P$, such that $PM=PN$. The circles $\omega_1$, $\omega_2$ meet $MN$ at $A, B$. The lines $PA, PB$ meet $\omega_1, \omega_2$ at $C, D$. Show that $\angle BCN=\angle ADM$.