Problem

Source: Romania 3rd JBMO TST 2023 P4

Tags: algebra, absolute value



Let be $a$ be positive real number. Prove that there are no real numbers $b$ and $c$, with $b < c$, so that for any distinct numbers $x, y \in (b, c)$ we have $|\frac{x+y} {x-y}| \leq a$.