DanDumitrescu 14.04.2023 05:06 We consider real positive numbers a,b,c such that a+b+c=3. Prove that a2+b2+c2+a2b+b2c+c2a≥6.
sqing 14.04.2023 05:33 DanDumitrescu wrote: We consider real positive numbers a,b,c such that a+b+c=3. Prove that a2+b2+c2+a2b+b2c+c2a≥6. https://artofproblemsolving.com/community/c6h1653353p10467212 https://artofproblemsolving.com/community/c6h1621344p11151417
sqing 14.04.2023 08:28 raigeki173 wrote: a2+b2+c2+(a2b+b)+(b2c+c)+(c2a+a)≥(a+b+c)2 https://artofproblemsolving.com/community/c6h1653353p10468198