The diagonals of a rectangle $ABCD$ meet at point $E$. A circle centered at $E$ lies inside the rectangle. Let $CF$, $DG$, $AH$ be the tangents to this circle from $C$, $D$, $A$; let $CF$ meet $DG$ at point $I$, $EI$ meet $AD$ at point $J$, and $AH$ meet $CF$ at point $L$. Prove that $LJ$ is perpendicular to $AD$.
Problem
Source: Sharygin 2023 - P2 (Grade-8)
Tags: geometry, rectangle, perpendicular lines, Sharygin Geometry Olympiad, Sharygin 2023