The circle $\Omega$ with center $O$ is circumscribed to acute triangle $ABC$. Let $P$ be a point on the circumscribed circle of $OBC$, such that $P$ is inside $ABC$ and is different from $B$ and $C$. Bisectors of angles $BPA$ and $CPA$ intersect the sides $AB$ and $AC$ in points $E$ and $F.$ Prove that the incenters of triangles $PEF, PCA$ and $PBA$ are collinear.