Prove that in all triangles $\vartriangle ABC$ with $\angle A = 2 \angle B$ it holds that, if $D$ is the foot of the perpendicular from $C$ to the perpendicular bisector of $AB$, $\frac{AC}{DC}$ is constant for any value of $\angle B$.
Problem
Source: 2022 Mathematics Regional Olympiad of Mexico West P4
Tags: ratio, geometry, fixed, equal angles