Given a $\triangle ABC$, $\angle A=45^\circ$, $O$ is the circumcenter and $H$ is the orthocenter of $\triangle ABC$. $M$ is the midpoint of $\overline{BC}$, and $N$ is the midpoint of $\overline{OH}$. Prove that $\angle BAM=\angle CAN$.
Source: 2021 IMOC qualification problem, G3
Tags: IMOC, geometry
Given a $\triangle ABC$, $\angle A=45^\circ$, $O$ is the circumcenter and $H$ is the orthocenter of $\triangle ABC$. $M$ is the midpoint of $\overline{BC}$, and $N$ is the midpoint of $\overline{OH}$. Prove that $\angle BAM=\angle CAN$.