Let $\sigma(n)$ the signature of $n$, and let $f(n)=|\{k\in [n,n+2019]|\sigma(k)<11\}|$. We notice that $f(n+1)$ can change value at most by one with respect to $f(n)$. We note that $f(1)=2020$ since if $k\leq 2020$, $\sigma(k)\leq \log_2(k)\leq \log_2(2020)<\log_2(2048)=11$. We can also find a $n$ such that $f(n)=0$, thanks to crt. We take $2020$ distinct primes $p_1,...,p_{2020}$ and $n$ so that $n\equiv 0\pmod{p_1^{11}}$, $n+1\equiv 0\pmod{p_2^{11}}$,... ,$n+2019\equiv 0\pmod{p_{2020}^{11}}$ so that $\sigma(n+k)\geq 11$ for every $k=0,...,2019$ and thus $f(n)=0$. Therefore, since $f$ is discretely continuous, there exists an $n$ so that $f(n)=1812$