Let $f(x)=a(3a+2c)x^2-2b(2a+c)x+b^2+(c+a)^2$ $(a,b,c\in R, a(3a+2c)\neq 0).$ If $$f(x)\leq 1$$for any real $x$, find the maximum of $|ab|.$
Problem
Source: China Zhuji
Tags: inequalities, China, algebra
sqing
07.08.2020 16:44
sqing wrote: Let $f(x)=a(3a+2c)x^2-2b(2a+c)x+b^2+(c+a)^2$ $(a,b,c\in R, a(3a+2c)\neq 0).$ If $$f(x)\leq 1$$for any real $x$, find the maximum of $|ab|.$
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Jjesus
16.09.2020 05:31
sqing wrote: sqing wrote: Let $f(x)=a(3a+2c)x^2-2b(2a+c)x+b^2+(c+a)^2$ $(a,b,c\in R, a(3a+2c)\neq 0).$ If $$f(x)\leq 1$$for any real $x$, find the maximum of $|ab|.$ What book is?
DrYouKnowWho
16.09.2020 08:40
From the water mark, it's from a chinese tutoring institution website that posts these contests and their solutions
sqing
16.09.2020 09:02
https://artofproblemsolving.com/community/c1252089_2020_south_east_mathematical_olympiad
yds
29.07.2021 09:13
you can try $x=a+c,y=2a+c$ and max is $\frac{3\sqrt{3}}{8}$