In $\triangle ABC$, $\angle BAC = 60^{\circ}$, point $D$ lies on side $BC$, $O_1$ and $O_2$ are the centers of the circumcircles of $\triangle ABD$ and $\triangle ACD$, respectively. Lines $BO_1$ and $CO_2$ intersect at point $P$. If $I$ is the incenter of $\triangle ABC$ and $H$ is the orthocenter of $\triangle PBC$, then prove that the four points $B,C,I,H$ are on the same circle.
Problem
Source: 2020 China North Mathematical Olympiad Basic Level P4
Tags: geometry, incenter, orthocenter, geometry solved, Circumcenter, cyclic quadrilateral, Spiral Similarity