Let $ABC$ be an acute-angled triangle inscribed in the circle $(O)$. Let $AD$ be the diameter of $(O)$. The points $M,N$ are chosen on $BC$ such that $OM\parallel AB, ON\parallel AC$. The lines $DM,DN$ cut $(O)$ again at $P,Q$. Prove that $BC=DP=DQ$. Tran Quang Hung, Vietnam