Problem

Source: 2018 Romania JBMO TST 1.3

Tags: geometry, geometric transformation, reflection, circumcircle, equal angles



Let $ABC$ be a triangle with $AB > AC$. Point $P \in (AB)$ is such that $\angle ACP = \angle ABC$. Let $D$ be the reflection of $P$ into the line $AC$ and let $E$ be the point in which the circumcircle of $BCD$ meets again the line $AC$. Prove that $AE = AC$.