For positive x,y, and z that satisfy the condition xyz=1, prove the inequality 3√x+y2z+3√y+z2x+3√z+x2y≤5(x+y+z)+98
Source: Ukraine TST 2013 p5
Tags: inequalities, algebra
For positive x,y, and z that satisfy the condition xyz=1, prove the inequality 3√x+y2z+3√y+z2x+3√z+x2y≤5(x+y+z)+98