Numbers $a, b, c$ are the length of the medians of some triangle. If $ab + bc + ac = 1$ prove that a) $a^2b + b^2c + c^2a > \frac13$ b) $a^2b + b^2c + c^2a > \frac12$ (I. Bliznets)
Problem
Source: Belarus 2010 TST 5.2
Tags: Medians, median, inequalities, geometric inequality, geometry