Problem

Source: Kosovo MO 2020 Grade 11, Problem 4

Tags: geometry, angle bisector, bisection, national olympiad, Olympiad, Kosovo



Let $\triangle ABC$ be a triangle and $\omega$ its circumcircle. The exterior angle bisector of $\angle BAC$ intersects $\omega$ at point $D$. Let $X$ be the foot of the altitude from $C$ to $AD$ and let $F$ be the intersection of the internal angle bisector of $\angle BAC$ and $BC$. Show that $BX$ bisects segment $AF$.