A cyclic quadrilateral $ABCD$ has circumcenter $O$, its diagonals $AC$ and $BD$ intersect at $G$. Let $P, Q, R, S$ be the circumcenters of $\vartriangle AGB, \vartriangle BGC, \vartriangle CGD, \vartriangle DGA$ respectively. Lines $P R$ and $QS$ intersect at $M$. Show that $M$ is the midpoint of $OG$.
Problem
Source: Thailand Mathematical Olympiad 2017 day 1 p2
Tags: geometry, Circumcenter, Cyclic, cyclic quadrilateral, midpoint