Problem

Source: I International Festival of Young Mathematicians Sozopol 2010, Theme for 10-12 grade

Tags: geometry



Let $\Delta ABC$ be an isosceles triangle with base $AB$. Point $P\in AB$ is such that $AP=2PB$. Point $Q$ from the segment $CP$ is such that $\angle AQP=\angle ACB$. Prove that $\angle PQB=\frac{1}{2}\angle ACB$.