Let $ k $ be a natural number. A function $ f:S:=\left\{ x_1,x_2,...,x_k\right\}\longrightarrow\mathbb{R} $ is said to be additive if, whenever $ n_1x_1+n_2x_2+\cdots +n_kx_k=0, $ it holds that $ n_1f\left( x_1\right)+n_2f\left( x_2\right)+\cdots +n_kf\left( x_k\right)=0, $ for all natural numbers $ n_1,n_2,...,n_k. $ Show that for every additive function and for every finite set of real numbers $ T, $ there exists a second function, which is a real additive function defined on $ S\cup T $ and which is equal to the former on the restriction $ S. $