CatalinBordea 28.09.2018 12:10 Find all natural numbers $ n,x,y $ such that $ \big| 2^x-n^{y+1}\big| =1 . $
LorRamos 28.09.2018 16:00 From Mihailescu's theorem, we get the only solution (n,x,y)=(3,3,1), which is valid for the case when expression in absolute value is -1. When the expression is equal to 1, again from Mihailescu we have no solution.