In triangle $ABC$, $\angle ACB=50^{\circ}$ and $\angle CBA=70^{\circ}$. Let $D$ be a foot of perpendicular from point $A$ to side $BC$, $O$ circumcenter of $ABC$ and $E$ antipode of $A$ in circumcircle $ABC$. Find $\angle DAE$
Problem
Source: Regional Olympiad - Federation of Bosnia and Herzegovina 2013
Tags: geometry, circumcircle, antipode