8 should divide the given number so 450+z is divisible by 8 and therefore z=6. Then 9 divides the given number and so 9 should divide x+y+1. Also 11 should divide 1+x+4+z-3-y-5=x+z-y-3=x-y+3. Then we have 4 cases: (1) x-y+3=11 and x+y+1=9. (2) x-y+3=11 and x+y+1=18. (3) x-y+3=0 and x+y+1=9. (4) x-y+3=0 and x+y+1=18. We then get the solution (if you meant x, y and z are digits): (x, y, z) = (8, 0, 6).

792's dividers are 11,9,8 so from the last 3 digit z must be 6 also in modula 11 x=y-8 so if we write in the number and look at it in modula 9 x will be 8 and y will be 0