Problem

Source: Serbian JBMO TST 2018, problem 2

Tags: inequalities, algebra, Serbian competition



Show that for $a,b,c > 0$ the following inequality holds: $\frac{\sqrt{ab}}{a+b+2c}+\frac{\sqrt{bc}}{b+c+2a}+\frac{\sqrt{ca}}{c+a+2b} \le \frac {3}{4}$.