is the answer Click to reveal hidden text

? If yes i'll post my solution. Sorry i read the question incorrect

I get $45$ Solution: obvious, that we can take only one number from pair $(a,100-a)$ If $100|ab \to 100|(100-a)b$so no matter what number from pair we take. So let we have numbers from $1$ to $50$ and remove from $51$ to $100$ We can take only one number from $(10,20,30,40,50)$ so we need remove $4$ numbers. We can take only one number from $(4,25)$ so we need remove one more number. For $n=45$ example : all numbers from $1$ to $49$, except $20,25,30,40$