On the inside of the triangle $ABC$ a point $P$ is chosen with $\angle BAP = \angle CAP$. If $\left | AB \right |\cdot \left | CP \right |= \left | AC \right |\cdot \left | BP \right |= \left | BC \right |\cdot \left | AP \right |$ , find all possible values of the angle $\angle ABP$.