Problem

Source: Iran TST 2017, Exam 1, Day 1, Problem 1

Tags: algebra, inequalities, Iran, Iranian TST



Let $a,b,c,d$ be positive real numbers with $a+b+c+d=2$. Prove the following inequality: $$\frac{(a+c)^{2}}{ad+bc}+\frac{(b+d)^{2}}{ac+bd}+4\geq 4\left ( \frac{a+b+1}{c+d+1}+\frac{c+d+1}{a+b+1} \right).$$ Proposed by Mohammad Jafari