Problem

Source: Vietnam Mathematical Olympiad 2016, Day 1, Problem 1

Tags: algebra proposed, algebra, system of equations



Solve the system of equations $\begin{cases}6x-y+z^2=3\\ x^2-y^2-2z=-1\quad\quad (x,y,z\in\mathbb{R}.)\\ 6x^2-3y^2-y-2z^2=0\end{cases}$.