In a triangle $ABC$, $\angle B = 70^o$, $\angle C = 50^o$. A point $M$ is taken on the side $AB$ such that $\angle MCB = 40^o$ , and a point $N$ is taken on the side $AC$ such that $\angle NBC = 50^o$. Find $\angle NMC$.
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Tags: geometry, 1st edition
In a triangle $ABC$, $\angle B = 70^o$, $\angle C = 50^o$. A point $M$ is taken on the side $AB$ such that $\angle MCB = 40^o$ , and a point $N$ is taken on the side $AC$ such that $\angle NBC = 50^o$. Find $\angle NMC$.