In the isoceles triangle $ABC$ with $AB=AC$, $D$ and $E$ are points on $AB$ and $AC$ respectively such that $AD=CE$ and $DE=BC$. Suppose $\angle AED=18^{\circ}$. Find the size of $\angle BDE$ in degrees.
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YESMAths
03.06.2014 20:22
SMOJ wrote: In the isoceles triangle $ABC$ with $AB=AC$, $D$ and $E$ are points on $AB$ and $AC$ respectively such that $AD=CE$ and $DE=BC$. Suppose $\angle AED=18^{\circ}$. Find the size of $\angle BDE$ in degrees. Are you sure SMOJ that $DE=BC$?
SMOJ
04.06.2014 08:10
Pretty sure
HapaxOromenon
07.05.2018 21:25
YESMAths wrote: SMOJ wrote: In the isoceles triangle $ABC$ with $AB=AC$, $D$ and $E$ are points on $AB$ and $AC$ respectively such that $AD=CE$ and $DE=BC$. Suppose $\angle AED=18^{\circ}$. Find the size of $\angle BDE$ in degrees. Are you sure SMOJ that $DE=BC$? Answer is 42 degrees, by some trig and algebra.