From \(\frac{x}{y} > \frac{a}{b}\), it follows that \(xb > ya\), so \(xb - ya \geq 1\). Similarly, it is shown that \(at - bz \geq 1\). We multiply the first inequality by \(t\), the second by \(y\), and add the obtained relations; we deduce that \(bxt - byz \geq t + y\), meaning \(b \geq t + y\). Similarly, it is demonstrated that \(a \geq x + z\). By multiplying these inequalities, the requirement of the problem follows.