Let $D,E,F$ be the midpoints of $BC$ ,$CA$, $AB$ in $\vartriangle ABC$ such that $AD= 9$, $BE= 12$, $CF= 15$. Calculate the area of $\vartriangle ABC$
Problem
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Tags: geometry
MrRandomness
30.12.2021 14:07
Area=$\frac{4}{3}\sqrt{s_m(s_m-a)(s_m-b)(s_m-c)}$
where, $s_m=\frac{m_1+m_2+m_3}{2}$
$m_1, m_2$ and $m_3$ are length of medians
Aiden-1089
02.10.2024 10:26
Area is $\frac{4}{3} \cdot \frac{1}{2} \cdot 9 \cdot 12 = 72$.