parmenides51 01.10.2021 21:52 Let a and b be positive integers such that 2a2+a=3b2+b. Prove that a−b is a perfect square.
rafaello 01.10.2021 22:56 The given is equivalent to (a−b)(2a+2b+1)=b2. Note that there are no primes p such that p∣a−b and p∣2a+2b+1, otherwise since then also p∣b, we get that p∣a and thus p∣1. Hence, a−b and 2a+2b+1 must be perfect squares.