Let the real numbers $x, y, z$ be such that $x + y + z = 0$. Prove that $$6(x^3 + y^3 + z^3)^2 \le (x^2 + y^2 + z^2)^3.$$
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Tags: algebra, inequalities
Let the real numbers $x, y, z$ be such that $x + y + z = 0$. Prove that $$6(x^3 + y^3 + z^3)^2 \le (x^2 + y^2 + z^2)^3.$$