Given a function p(x)=ax5+bx4+cx3+dx2+ex+f. Each coefficient a,b,c,d,e, andf is equal to either 1 or −1. If p(2)=11, what is the value of p(3)?
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Tags: algebra, polynomial
Bratin_Dasgupta
21.09.2021 20:15
https://www.chegg.com/homework-help/questions-and-answers/1-find-sum-integers-n-property-n-n-2021-perfect-squares-2-given-function-p-x-ax-5-bx-4-cx--q83106499
parmenides51
21.09.2021 20:37
Bratin_Dasgupta wrote: https://www.chegg.com/homework-help/questions-and-answers/1-find-sum-integers-n-property-n-n-2021-perfect-squares-2-given-function-p-x-ax-5-bx-4-cx--q83106499 I believe that there is no point in linking to a non free source, as we cannot see the answer without having registered
climbmountain
22.09.2021 01:33
p(2)=32a+16b+8c+4d+2e+f=11 Note that 32−16−8+4−2+1=11 Thus, p(x)=x5−x4−x3+x2−x+1 p(3)=243−81−27+9−3+1=142
OlympusHero
22.09.2021 01:59
We have 32−16−8+4−2+1=11, so our polynomial is x5−x4−x3+x2−x+1. Our answer is 35−34−33+32−3+1=142.
#YUH
kante314
22.09.2021 02:08
We have
32a+16b+8c+4d+2e+f=11After testing some we see that 32−16−8+4−2+1=11Thus our polynomial is
x5−x4−x3+x2−x+1Plugging in x=3 gives
35−34−33+32−3+1=243−81−27+9−3+1=142
Arrowhead575
22.09.2021 02:41
Together we ascertain that this simplifies to 32−16−8+4−2+1=11, so our quintic is k5−k4−k3+k2−k+1. Our answer is 35−34−33+32−3+1=142.
#YEUH
OofPirate
22.09.2021 06:48
Note that the function when p(2) is equal to p(2)=32a+16b+8c+4d+2e+1. By some means, I had found that a=1, b=−1, c=−1, d=1, e=−1, and f=1. Hence, the following is the function: p(x)=x5−x4−x3+x2−x+1. p(3)=243−81−27+9−3+1. p(3)=142.