In a triangle, the ratio of the interior angles is $1 : 5 : 6$, and the longest side has length $12$. What is the length of the altitude (height) of the triangle that is perpendicular to the longest side?
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Tags: altitude, Triangle, geometry
19.09.2020 03:13
19.09.2020 03:14
I don't get this question..."triangle that is perpendicular to the longest side"??
19.09.2020 03:15
franzliszt wrote: I don't get this question..."triangle that is perpendicular to the longest side"?? read the words that are right before it.
19.09.2020 03:16
Still don't get it. "What is the length of the altitude (height) of the triangle that is perpendicular to the longest side?" How to make a triangle perpendicular to the longest side?
19.09.2020 03:19
franzliszt wrote: Still don't get it. "What is the length of the altitude (height) of the triangle that is perpendicular to the longest side?" How to make a triangle perpendicular to the longest side? It means "What is the length of the altitude that is perpendicular to the longest side." Like in a 30-40-50 triangle that height is $24$
19.09.2020 03:24
Oh then this is bashy? You do LoS bash to find the sides. Then use Heron's. Then set and equation to find the altitude.
19.09.2020 05:26
A non-bashing sol., it is a 15-75-90 triangle, so we have \[\frac{1}{2}(12\sin 15)(12\cos 15)=\frac{1}{2}(12)(h) \implies h=12 \sin 15 \cos 15=6\sin 30=\boxed{3}\]